Dear all,
I am designing a non-inferiority trial that compares three groups of subjects receiving different intraocular lenses. The primary outcome that I wanted to look at was the binocular vision at intermediate distance postoperatively.
Nearly all the tutorials online talked about using artbin, and proportions as a way to calculate the sample size.
May I know if it is feasible to use means instead?
e.g.
Instead of using "proportions of eyes exceeding a certain level of vision"
can I calculate the sample size by
stating the previously reported "mean visual acuity" of the two study lenses with their respective SD?
Based on published results of other cohort studies
I gathered the below information
binocular intermediate VA
- lens 1 (control) : 0.24 +/= 0.14
- lens 2 (study lens) : 0.05 +/- 0.1
If I use normal t test
. power twomeans 0.24 0.05, sd1(0.14) sd2(0.1)
Performing iteration ...
Estimated sample sizes for a two-sample means test
Satterthwaite's t test assuming unequal variances
Ho: m2 = m1 versus Ha: m2 != m1
Study parameters:
alpha = 0.0500
power = 0.8000
delta = -0.1900
m1 = 0.2400
m2 = 0.0500
sd1 = 0.1400
sd2 = 0.1000
Estimated sample sizes:
N = 16
N per group = 8
Is this 8 per group - for 'superiority trial' rather than non-inferiority?
In my study design, there are TWO experimental groups - where I implant the study lens in dominant eye in one group, and non-dominant eye in one group.
- should I take into account of this third group during my sample size calculation? My original thought was to use the dominant eye vs control group only.
Thank you so much!
Kam
I am designing a non-inferiority trial that compares three groups of subjects receiving different intraocular lenses. The primary outcome that I wanted to look at was the binocular vision at intermediate distance postoperatively.
Nearly all the tutorials online talked about using artbin, and proportions as a way to calculate the sample size.
May I know if it is feasible to use means instead?
e.g.
Instead of using "proportions of eyes exceeding a certain level of vision"
can I calculate the sample size by
stating the previously reported "mean visual acuity" of the two study lenses with their respective SD?
Based on published results of other cohort studies
I gathered the below information
binocular intermediate VA
- lens 1 (control) : 0.24 +/= 0.14
- lens 2 (study lens) : 0.05 +/- 0.1
If I use normal t test
. power twomeans 0.24 0.05, sd1(0.14) sd2(0.1)
Performing iteration ...
Estimated sample sizes for a two-sample means test
Satterthwaite's t test assuming unequal variances
Ho: m2 = m1 versus Ha: m2 != m1
Study parameters:
alpha = 0.0500
power = 0.8000
delta = -0.1900
m1 = 0.2400
m2 = 0.0500
sd1 = 0.1400
sd2 = 0.1000
Estimated sample sizes:
N = 16
N per group = 8
Is this 8 per group - for 'superiority trial' rather than non-inferiority?
In my study design, there are TWO experimental groups - where I implant the study lens in dominant eye in one group, and non-dominant eye in one group.
- should I take into account of this third group during my sample size calculation? My original thought was to use the dominant eye vs control group only.
Thank you so much!
Kam
Comment