Loop forv

[Vera Schmidt]

Hi guys,

I try to wirte my first loop, but it does not work well. Hopefully, you may help.

I have data of an experiment which obtains 32 rounds. I would like to rename the variables, e.g., Player.1.income => income1.

Due to my research, I started with the follwing loop:

forv num=1/32 {
drop Player.`num'.income
}
But what is coming next? I only defined the "first part" and do not tell Stata to change it into income1.

Im looking forward to hearing from you!

[Ken Chui]

Can you double check your data and make sure the variable name is really "Player.1.income"? In Stata period (.) is not allowed in variable names.

Assuming there is no period, a possible

forvalues x = 1/32{
rename Player`x'income income`x'
}

[Vera Schmidt]

Wow, yet so simple. Many thanks & works well!

[Clyde Schechter]

If a purpose of this is to practice writing loops, then the solution in #2 is optimal.

But if the purpose is to write production code, even simpler is:

rename (Player*income) (income*)

which involves no loop at all.