Dear Statalisters,
I am trying to test for an inversed U-shaped between credit risk index and adjusted Lerner index(A measure of market power in the banking market).
To test for a U-shaped pattern between edit risk index and adjusted Lerner index I used a random-effects negative binomial model (supported by a Hausman test - xtnberg) including the direct (significant and positive) and the squared term of my Lerner Index. To corroborate this pattern of findings I would like to conduct a Sasabuchi (1980) test for an inverted U-shape, however I am not sure whether the right command was used to perform Sasabuchi test.
Followed by
Any idea on how to interpret these results? Does this mean that since we reject the null hypothesis based on p-value, that we should accept the H1 (direct U-shape) which is confirmed by the regressions (positive coefficient of Lerner^2):
Can you please confirm that this is the way to perform Sasabuchi test or I have to run another/different test in order to get the required result?
Many thanks in advance for your always precious help,
Petko Bachvarov
I am trying to test for an inversed U-shaped between credit risk index and adjusted Lerner index(A measure of market power in the banking market).
To test for a U-shaped pattern between edit risk index and adjusted Lerner index I used a random-effects negative binomial model (supported by a Hausman test - xtnberg) including the direct (significant and positive) and the squared term of my Lerner Index. To corroborate this pattern of findings I would like to conduct a Sasabuchi (1980) test for an inverted U-shape, however I am not sure whether the right command was used to perform Sasabuchi test.
Code:
Fixed-effect (Hausman test - xtnberg) xtnbreg llrgl car adjlerner adjlerner2 insitution ownership_concentration cir deposit_asset loan_asset otherearningassets incomediversity size tier1 fundingragility luqidasset logz gdp_growth inflation crisis_d listed_d, fe
Code:
Lind and Mehlum's procedure for testing U-shaped relationships or Sasabuchi test utest adjlerner adjlerner2, prefix(llrgl)
Code:
My results are the following: Conditional FE negative binomial regression Number of obs = 3124 Group variable: y Number of groups = 14 Obs per group: min = 223 avg = 223.1 max = 225 Wald chi2(19) = 95.47 Log likelihood = -481.71589 Prob > chi2 = 0.0000 ------------------------------------------------------------------------------ llrgl | Coef. Std. Err. z P>|z| [95% Conf. Interval] -------------+---------------------------------------------------------------- car | .0480899 .3682911 0.13 0.896 -.6737474 .7699271 adjlerner | -5.870174 1.569279 -3.74 0.000 -8.945904 -2.794444 adjlerner2 | 7.036934 1.943191 3.62 0.000 3.22835 10.84552 insitution | -.1541609 .1247337 -1.24 0.216 -.3986344 .0903125 ownership~on | .0115567 .2493661 0.05 0.963 -.4771918 .5003052 cir | .0020299 .002605 0.78 0.436 -.0030758 .0071356 deposit_as~t | .686342 .4698969 1.46 0.144 -.2346389 1.607323 loan_asset | -2.129252 .5312894 -4.01 0.000 -3.17056 -1.087944 otherearni~s | .216634 .346283 0.63 0.532 -.4620682 .8953361 incomedive~y | .142058 .1615877 0.88 0.379 -.174648 .458764 size | .0747654 .039163 1.91 0.056 -.0019926 .1515234 tier1 | .0816059 .2788698 0.29 0.770 -.464969 .6281807 fundingrag~y | .0959053 .4705931 0.20 0.839 -.8264402 1.018251 luqidasset | .860141 .4811945 1.79 0.074 -.082983 1.803265 logz | .0032852 .0652955 0.05 0.960 -.1246917 .1312621 gdp_growth | -5.295671 1.911873 -2.77 0.006 -9.042874 -1.548468 inflation | -.130405 1.155299 -0.11 0.910 -2.39475 2.13394 crisis_d | .0278075 1.120135 0.02 0.980 -2.167616 2.223231 listed_d | .356337 .1745903 2.04 0.041 .0141463 .6985277 _cons | 13.40707 203.6382 0.07 0.948 -385.7164 412.5306 ------------------------------------------------------------------------------ . utest adjlerner adjlerner2, prefix(llrgl) (325 missing values generated) Specification: f(x)=x^2 Extreme point: .4170974 Test: H1: U shape vs. H0: Monotone or Inverse U shape ------------------------------------------------- | Lower bound Upper bound -----------------+------------------------------- Interval | -.1606019 .9939588 Slope | -8.130464 8.11867 t-value | -3.729346 3.42437 P>|t| | .0000977 .0003121 ------------------------------------------------- Overall test of presence of a U shape: t-value = 3.42 P>|t| = .000312 .
Can you please confirm that this is the way to perform Sasabuchi test or I have to run another/different test in order to get the required result?
Many thanks in advance for your always precious help,
Petko Bachvarov
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