Dear all,
I think this an easy question but I got stuck.
For a seminal replication study, I would like to plot a line graph showing the means of my variable of interest and combine this with the confidence intervals.
I can use ciplot, ci and statsby, but I am quite uncommon with both latter commands.
I also found the option of adding a rcap graph, but I haven't figured out, how to compute the high and low values the confidence level (95%) of each observation (mean) of my variable in time as I am working with panel data.
The code is the following:
T1 is the treatment dummy (0 = control, 1=treated). I know that ciplot stores upper and lower values as scalars. My main problem is working with panel data, as I need for every year the CI...
I am using Stata 15.1
Thank you very much in advance.
Aline
I think this an easy question but I got stuck.
For a seminal replication study, I would like to plot a line graph showing the means of my variable of interest and combine this with the confidence intervals.
I can use ciplot, ci and statsby, but I am quite uncommon with both latter commands.
I also found the option of adding a rcap graph, but I haven't figured out, how to compute the high and low values the confidence level (95%) of each observation (mean) of my variable in time as I am working with panel data.
The code is the following:
Code:
// Figure 3 by syear T1, sort: egen meannoabs = mean(leadnoabs) * without rap twoway (line meannoabs syear if T1 == 1 & syear!=1996) (line meannoabs syear if T1 == 0 & syear!=1996) , legend(order(1 "Treatment" 2 "Control")) scheme(sj) name(graph3a, replace) gen hi = meannoabs+1.96*se(meannoabs) gen lo = meannoabs-1.96*se(meannoabs) * just rcap CI twoway (rcap meannoabs hi lo if T1==1) (rcap meannoabs hi lo if T1==0) * combined twoway (line meannoabs syear if T1 == 1 & syear!=1996) (line meannoabs syear if T1 == 0 & syear!=1996) (rcap meannoabs hi lo if T1==1) (rcap meannoabs hi lo if T1==0), legend(order(1 "Treatment" 2 "Control")) scheme(sj) *graph export
I am using Stata 15.1
Thank you very much in advance.
Aline
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