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  • #16
    Hello!

    I'm trying to produce something similar to the figure 3 of Beck, Levine, and Levkov (2010). Unlike the paper has 10 pre periods and 15 post periods, I have 3 pre periods and 2 post periods. I wonder how this part of the code can be revised to reflect I have 3 pre and 2 post periods?
    Code:
    matrix M = r(table)
    scalar x = 0
    forvalues i = -10(1)15 {
        if `i' != 0 {
            local j = cond(`i' < 0, `i'+11, `i'+10)
            replace b = M[1, `j'] if _tintra == `i'
            replace LB = M[5, `j'] if _tintra == `i'
            replace UB = M[6, `j'] if _tintra == `i'
        }
        if `i' < 0 {
            scalar x = x + M[1, `j']
        }
    }
    scalar x = x/10
    So for i = -10(1)15 I shall change it to i = -3(1)2, what about the part below?
    Code:
            local j = cond(`i' < 0, `i'+11, `i'+10)
            replace b = M[1, `j'] if _tintra == `i'
            replace LB = M[5, `j'] if _tintra == `i'
            replace UB = M[6, `j'] if _tintra == `i'
    As for scalar x = x/10, I suppose I need to change it to 3, as I have 3 pre periods.


    Thanks a lot,
    Flora

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