I have 30 participants that have been matched/paired on 5 potential confounders, 15 have arthritis and 15 are asymptomatic. I want to measure the difference of a continuous outcome variable (a measure of boney alignment) between those with and without arthritis, under four different conditions (4 different angles of knee flexion, which has some inherent error due to use of goniometry).
I have tried two approaches:
(i) xtmixed using the raw data (i.e. 30 groups, 120 observations, 4 observations per group) and including ARTHRITIS, i.ANGLE and i.PAIR in the fixed part of the model.
(ii) xtmixed using the simple difference method (i.e. 15 groups, 60 observations, 4 obs per group) and including i.ANGLE, but not ARTHRITIS or i.PAIR in the fixed portion since I am modeling the difference due to arthritis by pair.
For both approaches, I have added the random portion as || PAIR: ANGLE, cov(un)
The results are substantially different, and I am not sure how to explain this, so not sure which approach is superior. How do I best model/estimate the effect of arthritis on alignment using (and statistically accounting for) a matched case-control design?
(i) B[ARTHRITIS] = -2.4 SE = 1.1 p= 0.02
(ii) _cons = -1.7 SE = 2.0 p = 0.396
Kind regards,
Erin Macri
I have tried two approaches:
(i) xtmixed using the raw data (i.e. 30 groups, 120 observations, 4 observations per group) and including ARTHRITIS, i.ANGLE and i.PAIR in the fixed part of the model.
(ii) xtmixed using the simple difference method (i.e. 15 groups, 60 observations, 4 obs per group) and including i.ANGLE, but not ARTHRITIS or i.PAIR in the fixed portion since I am modeling the difference due to arthritis by pair.
For both approaches, I have added the random portion as || PAIR: ANGLE, cov(un)
The results are substantially different, and I am not sure how to explain this, so not sure which approach is superior. How do I best model/estimate the effect of arthritis on alignment using (and statistically accounting for) a matched case-control design?
(i) B[ARTHRITIS] = -2.4 SE = 1.1 p= 0.02
(ii) _cons = -1.7 SE = 2.0 p = 0.396
Kind regards,
Erin Macri
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