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  • Hausman test of IIA - Interpretation

    Dear all,

    I tested my 2011 data for IIA and got this result:

    qui mlogit outcomes $xlist [pw=pfwgtpop], baseoutcome(0) vce(cluster hh_id) allbaselevels
    estimates store all
    qui mlogit outcomes $xlist if outcomes<3 [pw=pfwgtpop], baseoutcome(0) vce(cluster hh_id) allbaselevels
    estimates store no3
    hauman all no3, alleqs force

    Result:
    chi2(50) = -44.07
    chi2<0 ==> model fitted on these data fails to meet the asymptotic assumptions of the Hausman test

    Doing the same for 2013, I get:
    chi2(50) = 65.97
    Prob>chi2 = 0.0645

    And for 2014:
    chi2(50) = 19.33
    Prob>chi2 = 1.000

    First, can anyone help me interpret this? From what I've read, a negative chi2 quite basically means that IIA is not violated. But what do positive chi2 results mean, and their P-values? Why didn't I get a P-value when I got a negative chi2? Do my 2013 and 2014 data also not violate the IIA assumption?

    Second, this is the Hausman test for only one instance where I remove the 3rd outcome. Do I need to conduct it removing all the outcomes one at a time? Do I switch the base outcomes as well?

    Thanks for your help!
    Last edited by Jill Adona; 21 Feb 2016, 19:08.

  • #2
    Jill:
    Example 2 under -hausman- entry in Stata .pdf manual (pages 938-41) covers what you're interested in.

    Kind regards,
    Carlo
    (StataNow 18.5)

    Comment


    • #3
      Dear Jill,

      A couple of points here:

      a) If you are testing the IIA, you should not be using clustered (or robust) standard errors. That will have an impact on the outcome of the test.

      b) I would not say that a negative Hausman statistic can be interpreted as supporting the null; quite on the contrary.

      Finally, there are much better ways to test the IIA assumption.

      Best regards,

      Joao

      Comment


      • #4
        Dear Joao, yes, thanks, I realized that I shouldn't be using vce(cluster)!

        Carlo, I read up on that and it helped a lot, thank you!

        Comment


        • #5
          Joao Santos Silva and Carlo Lazzaro To establish IIA for a multinomial logistic regression model which has three a category dependent variable called DV (1 = no college, 2 = immediate enrollment in college, and 3 = on-time enrollment in college; base category is 2) do I need to do the hausman on all combinations? So, allcats+no3 and allcats+no1? Or can I just do it on allcats+no3 and establish IIA?

          Comment


          • #6
            Dear Scott Rick,

            You can use just one but, as I said above, there are better ways to test the IIA.

            Best wishes,

            Joao

            Comment


            • #7
              Thank you Joao Santos Silva

              Comment


              • #8
                Joao Santos Silva, you previously mentioned there are better ways to test the IIA other than the Hausman test. Can you recommend other ways to test?

                Thank you!

                Comment


                • #9
                  Dear Hugo Castro Silva,

                  In my experience, this works much better and it is easy to implement.

                  Best wishes,

                  Joao

                  Comment


                  • #10
                    Originally posted by Joao Santos Silva View Post
                    Dear Hugo Castro Silva,

                    In my experience, this works much better and it is easy to implement.

                    Best wishes,

                    Joao
                    Thank you! I will have a look.

                    Comment

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